Liste de toutes les colonnes d'index et d'index dans la database SQL Server

Comment puis-je get une list de toutes les colonnes d'index et d'index dans SQL Server 2005+? Le plus proche que je pourrais get est:

select s.name, t.name, i.name, c.name from sys.tables t inner join sys.schemas s on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id where i.index_id > 0 and i.type in (1, 2) -- clustered & nonclustered only and i.is_primary_key = 0 -- do not include PK indexes and i.is_unique_constraint = 0 -- do not include UQ and i.is_disabled = 0 and i.is_hypothetical = 0 and ic.key_ordinal > 0 order by ic.key_ordinal 

Ce qui n'est pas exactement ce que je veux.
Ce que je veux, c'est de listr tous les index définis par l'user ( ce qui signifie pas d'index qui supportent des contraintes et des keys primaires uniques ) avec toutes les colonnes (ordonnées par la façon dont elles apparaissent dans la définition d'index) plus autant de métadonnées que possible.

    Vous pouvez consulter deux vues de catalogue "sys":

     select * from sys.indexes 

     select * from sys.index_columns 

    Ceux-ci vous donneront à peu près toutes les informations que vous pourriez vouloir sur les indices et leurs colonnes.

    EDIT: Cette requête est assez proche de ce que vous cherchez:

     SELECT TableName = t.name, IndexName = ind.name, IndexId = ind.index_id, ColumnId = ic.index_column_id, ColumnName = col.name, ind.*, ic.*, col.* FROM sys.indexes ind INNER JOIN sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id INNER JOIN sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id INNER JOIN sys.tables t ON ind.object_id = t.object_id WHERE ind.is_primary_key = 0 AND ind.is_unique = 0 AND ind.is_unique_constraint = 0 AND t.is_ms_shipped = 0 ORDER BY t.name, ind.name, ind.index_id, ic.index_column_id; 

    Vous pouvez utiliser sp_helpindex pour afficher tous les index d'une table.

     EXEC sys.sp_helpindex @objname = N'User' -- nvarchar(77) 

    Et pour tous les index, vous pouvez parcourir sys.objects pour get tous les index de chaque table.

    Aucun de ce qui précède n'a fait le travail pour moi, mais cela:

     -- KDF9's concise index list for SQL Server 2005+ (see below for 2000) -- includes schemas and primary keys, in easy to read format -- with unique, clustered, and all ascending/descendings in a single column -- Needs simple manual add or delete to change maximum number of key columns -- but is easy to understand and modify, with no UDFs or complex logic -- SELECT schema_name(schema_id) as SchemaName, OBJECT_NAME(si.object_id) as TableName, si.name as IndexName, (CASE is_primary_key WHEN 1 THEN 'PK' ELSE '' END) as PK, (CASE is_unique WHEN 1 THEN '1' ELSE '0' END)+' '+ (CASE si.type WHEN 1 THEN 'C' WHEN 3 THEN 'X' ELSE 'B' END)+' '+ -- B=basic, C=Clustered, X=XML (CASE INDEXKEY_PROPERTY(si.object_id,index_id,1,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,2,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,3,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,4,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,5,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ (CASE INDEXKEY_PROPERTY(si.object_id,index_id,6,'IsDescending') WHEN 0 THEN 'A' WHEN 1 THEN 'D' ELSE '' END)+ '' as 'Type', INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,1) as Key1, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,2) as Key2, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,3) as Key3, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,4) as Key4, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,5) as Key5, INDEX_COL(schema_name(schema_id)+'.'+OBJECT_NAME(si.object_id),index_id,6) as Key6 FROM sys.indexes as si LEFT JOIN sys.objects as so on so.object_id=si.object_id WHERE index_id>0 -- omit the default heap and OBJECTPROPERTY(si.object_id,'IsMsShipped')=0 -- omit system tables and not (schema_name(schema_id)='dbo' and OBJECT_NAME(si.object_id)='sysdiagrams') -- omit sysdiagrams ORDER BY SchemaName,TableName,IndexName ------------------------------------------------------------------- -- or to generate creation scripts put a simple wrapper around that SELECT SchemaName, TableName, IndexName, (CASE pk WHEN 'PK' THEN 'ALTER '+ 'TABLE '+SchemaName+'.'+TableName+' ADD CONSTRAINT '+IndexName+' PRIMARY KEY'+ (CASE subssortingng(Type,3,1) WHEN 'C' THEN ' CLUSTERED' ELSE '' END) ELSE 'CREATE '+ (CASE subssortingng(Type,1,1) WHEN '1' THEN 'UNIQUE ' ELSE '' END)+ (CASE subssortingng(Type,3,1) WHEN 'C' THEN 'CLUSTERED ' ELSE '' END)+ 'INDEX '+IndexName+' ON '+SchemaName+'.'+TableName END)+ ' ('+ (CASE WHEN Key1 is null THEN '' ELSE Key1+(CASE subssortingng(Type,4+1,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key2 is null THEN '' ELSE ', '+Key2+(CASE subssortingng(Type,4+2,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key3 is null THEN '' ELSE ', '+Key3+(CASE subssortingng(Type,4+3,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key4 is null THEN '' ELSE ', '+Key4+(CASE subssortingng(Type,4+4,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key5 is null THEN '' ELSE ', '+Key5+(CASE subssortingng(Type,4+5,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ (CASE WHEN Key6 is null THEN '' ELSE ', '+Key6+(CASE subssortingng(Type,4+6,1) WHEN 'D' THEN ' DESC' ELSE '' END) END)+ ')' as CreateIndex FROM ( ... ...listing SQL same as above minus the ORDER BY... ... ) as indexes ORDER BY SchemaName,TableName,IndexName ---------------------------------------------------------- -- For SQL Server 2000 the following should work -- change table names to sysindexes and sysobjects (no dots) -- change object_id => id, index_id => indid, -- change is_primary_key => (select count(constid) from sysconstraints as sc where sc.id=si.id and sc.status&15=1) -- change is_unique => INDEXPROPERTY(si.id,si.name,'IsUnique') -- change si.type => INDEXPROPERTY(si.id,si.name,'IsClustered') -- remove all references to schemas including schema name qualifiers, and the XML type -- add select where indid<255 and si.status&64=0 (to omit the text/image index and autostats) 

    Si vos noms incluent des espaces, ajoutez des crochets autour d'eux dans les scripts de création.

    Lorsque la dernière colonne Key est null, vous savez qu'il n'y en a aucune.

    Filtrer les keys primaires etc. comme dans la request d'origine est sortingvial.

    REMARQUE: Faites attention avec cette solution car elle ne distingue pas les colonnes indexées et incluses.

    –Court et doux:

     SELECT OBJECT_SCHEMA_NAME(T.[object_id],DB_ID()) AS [Schema], T.[name] AS [table_name], I.[name] AS [index_name], AC.[name] AS [column_name], I.[type_desc], I.[is_unique], I.[data_space_id], I.[ignore_dup_key], I.[is_primary_key], I.[is_unique_constraint], I.[fill_factor], I.[is_padded], I.[is_disabled], I.[is_hypothetical], I.[allow_row_locks], I.[allow_page_locks], IC.[is_descending_key], IC.[is_included_column] FROM sys.[tables] AS T INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id] INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id] INNER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id] WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP' ORDER BY T.[name], I.[index_id], IC.[key_ordinal] 

    La suite donne ce qui s'apparente au nom de table sp_helpindex

     select T.name as TableName, I.name as IndexName, AC.Name as ColumnName, I.type_desc as IndexType from sys.tables as T inner join sys.indexes as I on T.[object_id] = I.[object_id] inner join sys.index_columns as IC on IC.[object_id] = I.[object_id] and IC.[index_id] = I.[index_id] inner join sys.all_columns as AC on IC.[object_id] = AC.[object_id] and IC.[column_id] = AC.[column_id] order by T.name, I.name 

    Hé les gars, je ne suis pas passé mais j'ai obtenu ce que je voulais dans la requête postée par l'auteur original.

    Je l'ai utilisé (sans conditions / filters) pour mes besoins mais cela a donné des résultats incorrects

    Le problème principal était que les résultats obtenaient un produit croisé sans condition de jointure sur index_id

     SELECT S.NAME SCHEMA_NAME,T.NAME TABLE_NAME,I.NAME INDEX_NAME,C.NAME COLUMN_NAME FROM SYS.TABLES T INNER JOIN SYS.SCHEMAS S ON T.SCHEMA_ID = S.SCHEMA_ID INNER JOIN SYS.INDEXES I ON I.OBJECT_ID = T.OBJECT_ID INNER JOIN SYS.INDEX_COLUMNS IC ON IC.OBJECT_ID = T.OBJECT_ID INNER JOIN SYS.COLUMNS C ON C.OBJECT_ID = T.OBJECT_ID **AND IC.INDEX_ID = I.INDEX_ID** AND IC.COLUMN_ID = C.COLUMN_ID WHERE 1=1 ORDER BY I.NAME,I.INDEX_ID,IC.KEY_ORDINAL 

    Cela fonctionnera:

     DECLARE @IndexInfo TABLE (index_name varchar(250) ,index_description varchar(250) ,index_keys varchar(250) ) INSERT INTO @IndexInfo exec sp_msforeachtable 'sp_helpindex ''?''' select * from @IndexInfo 

    cela ne reurn le nom de la table et vous obtiendrez des avertissements pour toutes les tables sans index, si c'est un problème, vous pouvez créer une boucle sur les tables qui ont des index comme ceci:

     DECLARE @IndexInfoTemp TABLE (index_name varchar(250) ,index_description varchar(250) ,index_keys varchar(250) ) DECLARE @IndexInfo TABLE (table_name sysname ,index_name varchar(250) ,index_description varchar(250) ,index_keys varchar(250) ) DECLARE @Tables Table (RowID int not null identity(1,1) ,TableName sysname ) DECLARE @MaxRow int DECLARE @CurrentRow int DECLARE @CurrentTable sysname INSERT INTO @Tables SELECT DISTINCT t.name FROM sys.indexes i INNER JOIN sys.tables t ON i.object_id = t.object_id WHERE i.Name IS NOT NULL SELECT @MaxRow=@@ROWCOUNT,@CurrentRow=1 WHILE @CurrentRow<=@MaxRow BEGIN SELECT @CurrentTable=TableName FROM @Tables WHERE RowID=@CurrentRow INSERT INTO @IndexInfoTemp exec sp_helpindex @CurrentTable INSERT INTO @IndexInfo (table_name , index_name , index_description , index_keys) SELECT @CurrentTable , index_name , index_description , index_keys FROM @IndexInfoTemp DELETE FROM @IndexInfoTemp SET @CurrentRow=@CurrentRow+1 END --WHILE SELECT * from @IndexInfo 

    MODIFIER
    Si vous le souhaitez, vous pouvez filterr datatables, voici quelques exemples (ceux-ci fonctionnent pour l'une ou l'autre méthode):

     SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%primary key%' SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%nonclustered%' AND index_description LIKE '%clustered%' SELECT * FROM @IndexInfo WHERE index_description LIKE '%unique%' 
     with connect(schema_name,table_name,index_name,index_column_id,column_name) as ( select s.name schema_name, t.name table_name, i.name index_name, index_column_id, cast(c.name as varchar(max)) column_name from sys.tables t inner join sys.schemas s on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id where index_column_id=1 union all select s.name schema_name, t.name table_name, i.name index_name, ic.index_column_id, cast(connect.column_name + ',' + c.name as varchar(max)) column_name from sys.tables t inner join sys.schemas s on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id join connect on connect.index_column_id+1 = ic.index_column_id and connect.schema_name = s.name and connect.table_name = t.name and connect.index_name = i.name) select connect.schema_name,connect.table_name,connect.index_name,connect.column_name from connect join (select schema_name,table_name,index_name,MAX(index_column_id) index_column_id from connect group by schema_name,table_name,index_name) mx on connect.schema_name = mx.schema_name and connect.table_name = mx.table_name and connect.index_name = mx.index_name and connect.index_column_id = mx.index_column_id order by 1,2,3 

    J'ai eu besoin d'avoir des index particuliers, leurs colonnes d'index et leurs colonnes incluses aussi. Voici la requête que j'ai utilisée:

     SELECT INX.[name] AS [Index Name] ,TBL.[name] AS [Table Name] ,DS1.[IndexColumnsNames] ,DS2.[IncludedColumnsNames] FROM [sys].[indexes] INX INNER JOIN [sys].[tables] TBL ON INX.[object_id] = TBL.[object_id] CROSS APPLY ( SELECT STUFF ( ( SELECT ' [' + CLS.[name] + ']' FROM [sys].[index_columns] INXCLS INNER JOIN [sys].[columns] CLS ON INXCLS.[object_id] = CLS.[object_id] AND INXCLS.[column_id] = CLS.[column_id] WHERE INX.[object_id] = INXCLS.[object_id] AND INX.[index_id] = INXCLS.[index_id] AND INXCLS.[is_included_column] = 0 FOR XML PATH('') ) ,1 ,1 ,'' ) ) DS1 ([IndexColumnsNames]) CROSS APPLY ( SELECT STUFF ( ( SELECT ' [' + CLS.[name] + ']' FROM [sys].[index_columns] INXCLS INNER JOIN [sys].[columns] CLS ON INXCLS.[object_id] = CLS.[object_id] AND INXCLS.[column_id] = CLS.[column_id] WHERE INX.[object_id] = INXCLS.[object_id] AND INX.[index_id] = INXCLS.[index_id] AND INXCLS.[is_included_column] = 1 FOR XML PATH('') ) ,1 ,1 ,'' ) ) DS2 ([IncludedColumnsNames]) 

    C'est un moyen de sauvegarder dans les index. Vous pouvez utiliser SHOWCONTIG pour évaluer la fragmentation. Il listra tous les index pour la database ou la table, avec des statistics. Je voudrais mettre en garde que sur une grande database, il peut être long. Pour moi, l'un des avantages de cette approche est que vous n'avez pas besoin d'être un administrateur pour l'utiliser.

    –Show fragmentation info sur tous les index dans une database

     SET NOCOUNT ON USE pubs DBCC SHOWCONTIG WITH ALL_INDEXES GO 

    … remet NOCOUNT à OFF lorsque vous avez terminé

    –Show fragmentation info sur tous les index sur une table

     SET NOCOUNT ON USE pubs DBCC SHOWCONTIG (authors) WITH ALL_INDEXES GO 

    –Afficher les informations de fragmentation sur un index spécifique

     SET NOCOUNT ON USE pubs DBCC SHOWCONTIG (authors,aunmind) GO 

    Les travaux suivants sur SQL Server 2014/2016 ainsi que toute database Microsoft Azure SQL.

    Produit un jeu de résultats complet facilement exportable vers Bloc-notes / Excel pour découper et découper en dés et inclut

    1. Nom de la table
    2. Nom de l'index
    3. Description de l'index
    4. Colonnes indexées – Dans l'ordre
    5. Colonnes incluses – Dans l'ordre
      SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name' ,+ i.NAME AS 'index_name' ,LOWER(i.type_desc) + CASE WHEN i.is_unique = 1 THEN ', unique' ELSE '' END + CASE WHEN i.is_primary_key = 1 THEN ', primary key' ELSE '' END AS 'index_description' ,STUFF(( SELECT ', [' + sc.NAME + ']' AS "text()" FROM syscolumns AS sc INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id AND ic.column_id = sc.colid WHERE sc.id = so.object_id AND ic.index_id = i1.indid AND ic.is_included_column = 0 ORDER BY key_ordinal FOR XML PATH('') ), 1, 2, '') AS 'indexed_columns' ,STUFF(( SELECT ', [' + sc.NAME + ']' AS "text()" FROM syscolumns AS sc INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id AND ic.column_id = sc.colid WHERE sc.id = so.object_id AND ic.index_id = i1.indid AND ic.is_included_column = 1 FOR XML PATH('') ), 1, 2, '') AS 'included_columns' FROM sysindexes AS i1 INNER JOIN sys.indexes AS i ON i.object_id = i1.id AND i.index_id = i1.indid INNER JOIN sysobjects AS o ON o.id = i1.id INNER JOIN sys.objects AS so ON so.object_id = o.id AND is_ms_shipped = 0 INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id WHERE so.type = 'U' AND i1.indid < 255 AND i1.STATUS & 64 = 0 --index with duplicates AND i1.STATUS & 8388608 = 0 --auto created index AND i1.STATUS & 16777216 = 0 --stats no recompute AND i.type_desc <> 'heap' AND so.NAME <> 'sysdiagrams' ORDER BY table_name ,index_name; 

    Je suis venu avec celui-ci, qui me donne l'aperçu exact dont j'ai besoin. Ce qui est utile, c'est que vous obtenez une ligne par index dans laquelle les colonnes d'index sont agrégées.

     select o.name as ObjectName, i.name as IndexName, i.is_primary_key as [PrimaryKey], SUBSTRING(i.[type_desc],0,6) as IndexType, i.is_unique as [Unique], Columns.[Normal] as IndexColumns, Columns.[Included] as IncludedColumns from sys.indexes i join sys.objects o on i.object_id = o.object_id cross apply ( select subssortingng ( ( select ', ' + co.[name] from sys.index_columns ic join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 0 order by ic.key_ordinal for xml path('') ) , 3 , 10000 ) as [Normal] , subssortingng ( ( select ', ' + co.[name] from sys.index_columns ic join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 1 order by ic.key_ordinal for xml path('') ) , 3 , 10000 ) as [Included] ) Columns where o.[type] = 'U' --USER_TABLE order by o.[name], i.[name], i.is_primary_key desc 

    Puis-je hasarder une autre réponse à cette question saturée?

    Ceci est un remaniement libéral de la réponse de @marc_s, mélangé avec quelques trucs de @Tim Ford, avec l'objective d'avoir un set de résultats un peu plus propre et plus simple et l'affichage final et la command pour mon besoin actuel.

     SELECT OBJECT_SCHEMA_NAME(t.[object_id],DB_ID()) AS [Schema], t.[name] AS [TableName], ind.[name] AS [IndexName], col.[name] AS [ColumnName], ic.column_id AS [ColumnId], ind.[type_desc] AS [IndexTypeDesc], col.is_identity AS [IsIdentity], ind.[is_unique] AS [IsUnique], ind.[is_primary_key] AS [IsPrimaryKey], ic.[is_descending_key] AS [IsDescendingKey], ic.[is_included_column] AS [IsIncludedColumn] FROM sys.indexes ind INNER JOIN sys.index_columns ic ON ind.object_id = ic.object_id AND ind.index_id = ic.index_id INNER JOIN sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id INNER JOIN sys.tables t ON ind.object_id = t.object_id WHERE t.is_ms_shipped = 0 --ind.is_primary_key = 1 -- include or not pks, etc --AND ind.is_unique = 0 --AND ind.is_unique_constraint = 0 ORDER BY [Schema], TableName, IndexName, [ColumnId], ColumnName 

    Étant donné que votre profil indique que vous utilisez .NET, vous pouvez utiliser SMO (Server Managed Objects) par programmation … dans le cas contraire, les réponses ci-dessus sont fantastiques.

    La solution ci-dessus est élégante, mais selon MS, INDEXKEY_PROPERTY est déprécié. Voir: http://msdn.microsoft.com/en-us/library/ms186773.aspx

    basé sur le code de Tim Ford, c'est la bonne réponse:

      select tab.[name] as [table_name], idx.[name] as [index_name], allc.[name] as [column_name], idx.[type_desc], idx.[is_unique], idx.[data_space_id], idx.[ignore_dup_key], idx.[is_primary_key], idx.[is_unique_constraint], idx.[fill_factor], idx.[is_padded], idx.[is_disabled], idx.[is_hypothetical], idx.[allow_row_locks], idx.[allow_page_locks], idxc.[is_descending_key], idxc.[is_included_column], idxc.[index_column_id] from sys.[tables] as tab inner join sys.[indexes] idx on tab.[object_id] = idx.[object_id] inner join sys.[index_columns] idxc on idx.[object_id] = idxc.[object_id] and idx.[index_id] = idxc.[index_id] inner join sys.[all_columns] allc on tab.[object_id] = allc.[object_id] and idxc.[column_id] = allc.[column_id] where tab.[name] Like '%table_name%' and idx.[name] Like '%index_name%' order by tab.[name], idx.[index_id], idxc.[index_column_id] 

    Dans Oracle

     select CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME,CONNECYBY.COLUMN_NAME from ( select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,COLUMN_POSITION,sortingm(',' from sys_connect_by_path(COLUMN_NAME,',')) COLUMN_NAME from DBA_IND_COLUMNS start with COLUMN_POSITION = 1 connect by TABLE_OWNER = prior TABLE_OWNER and TABLE_NAME = prior TABLE_NAME and INDEX_NAME = prior INDEX_NAME and COLUMN_POSITION = prior COLUMN_POSITION + 1) CONNECYBY join ( select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,max(COLUMN_POSITION) COLUMN_POSITION from DBA_IND_COLUMNS group by TABLE_OWNER,TABLE_NAME,INDEX_NAME) MAX_CONNECYBY on ( CONNECYBY.SCHEMA_NAME = MAX_CONNECYBY.SCHEMA_NAME and CONNECYBY.TABLE_NAME = MAX_CONNECYBY.TABLE_NAME and CONNECYBY.INDEX_NAME = MAX_CONNECYBY.INDEX_NAME and CONNECYBY.COLUMN_POSITION = MAX_CONNECYBY.COLUMN_POSITION) order by CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME 

    Dans SQL Server avec

     CONNECTBY(SCHEMA_NAME,TABLE_NAME,INDEX_NAME,INDEX_COLUMN_ID,COLUMN_NAME) as ( select SCHEMAS.NAME SCHEMA_NAME , TABLES.NAME TABLE_NAME , INDEXES.NAME INDEX_NAME , INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID , cast(COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME from SYS.INDEXES join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID) join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID) join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID) join SYS.COLUMNS on ( INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID) where INDEX_COLUMNS.INDEX_COLUMN_ID = 1 union all select SCHEMAS.NAME SCHEMA_NAME , TABLES.NAME TABLE_NAME , INDEXES.NAME INDEX_NAME , INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID , cast(PRIOR.COLUMN_NAME + ',' + COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME from SYS.INDEXES join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID) join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID) join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID) join SYS.COLUMNS on ( INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID) join CONNECTBY as PRIOR on (SCHEMAS.NAME = PRIOR.SCHEMA_NAME and TABLES.NAME = PRIOR.TABLE_NAME and INDEXES.NAME = PRIOR.INDEX_NAME and INDEX_COLUMNS.INDEX_COLUMN_ID = PRIOR.INDEX_COLUMN_ID + 1)) select CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME,CONNECTBY.COLUMN_NAME from CONNECTBY join ( select SCHEMA_NAME , TABLE_NAME , INDEX_NAME , MAX(INDEX_COLUMN_ID) INDEX_COLUMN_ID from CONNECTBY group by SCHEMA_NAME,TABLE_NAME,INDEX_NAME) MAX_CONNECTBY on (CONNECTBY.SCHEMA_NAME = MAX_CONNECTBY.SCHEMA_NAME and CONNECTBY.TABLE_NAME = MAX_CONNECTBY.TABLE_NAME and CONNECTBY.INDEX_NAME = MAX_CONNECTBY.INDEX_NAME and CONNECTBY.INDEX_COLUMN_ID = MAX_CONNECTBY.INDEX_COLUMN_ID) order by CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME 

    Notez simplement que si vous souhaitez utiliser l'une des requêtes de travail ci-dessus pour scripter vos index, vous devez incorporer la colonne filter_definition de la table sys.indexes dans vos requêtes pour get la définition de filter des index non cluster dans SQL 2008+

    UN M

    Voici la meilleure façon de le faire:

     SELECT sys.tables.object_id, sys.tables.name as table_name, sys.columns.name as column_name, sys.indexes.name as index_name, sys.indexes.is_unique, sys.indexes.is_primary_key FROM sys.tables, sys.indexes, sys.index_columns, sys.columns WHERE (sys.tables.object_id = sys.indexes.object_id AND sys.tables.object_id = sys.index_columns.object_id AND sys.tables.object_id = sys.columns.object_id AND sys.indexes.index_id = sys.index_columns.index_id AND sys.index_columns.column_id = sys.columns.column_id) AND sys.tables.name = 'your_table_name' 

    Je préfère utiliser des jointures implicites, car il m'est plus facile de comprendre. Vous pouvez supprimer la reference object_id car vous n'en aurez pas besoin.

    À votre santé.

    Tout d'abord, veuillez noter que toutes les requêtes ci-dessus peuvent manquer ou incorporer par erreur les colonnes INCLUDE des indices. Il manque également dans certains l'ordre approprié et / ou l'option ASC / DESC des colonnes.

    Modifié la requête ci-dessus par jona. En passant, dans la plupart des bases de données que j'utilise, j'installe ma propre fonction d'agrégation CLR CONCATENATE, donc le code ci-dessous dépend de quelque chose comme ça. Les instructions SQL ci-dessus réduisent à un beaucoup plus maintenable:

     SELECT s.[name] AS [schema_name] , t.[name] AS [table_name] , i.[name] AS [index_name] , dbo.Concatenate(CASE WHEN ic.[key_ordinal] > 0 AND ic.[is_descending_key] = 1 THEN c.[name] + ' DESC' WHEN key_ordinal > 0 THEN c.[name] ELSE NULL END,',',1) AS [columns] , dbo.Concatenate(CASE WHEN ic.[is_included_column] = 1 THEN c.[name] ELSE NULL END,',',1) AS [includes] FROM sys.tables t INNER JOIN sys.schemas s ON t.[schema_id] = s.[schema_id] INNER JOIN sys.indexes i ON i.[object_id] = t.[object_id] INNER JOIN sys.index_columns ic ON ic.[object_id] = t.[object_id] AND ic.index_id = i.index_id INNER JOIN sys.columns c ON c.[object_id] = t.[object_id] AND ic.column_id = c.column_id GROUP BY s.[name] , t.[name] , i.[name] ORDER BY s.[name] , t.[name] , i.[name] 

    Il existe de nombreux agrégats de concaténation si votre environnement permet l'ajout de fonctions basées sur CLR.

    Pour les colonnes uniques par index:

     select s.name, t.name, i.name, i.index_id,c.name,c.column_id from sys.schemas s inner join sys.tables t on t.schema_id = s.schema_id inner join sys.indexes i on i.object_id = t.object_id inner join sys.index_columns ic on ic.object_id = t.object_id and ic.index_id=i.index_id inner join sys.columns c on c.object_id = t.object_id and ic.column_id = c.column_id where i.object_id = object_id('previous.account_1') order by index_id,column_id 

    La requête ci-dessous inclut toutes les informations pertinentes pour les index définis par l'user (pas d'index pour les contraintes uniques et les keys primaires) avec toutes les colonnes:

     SELECT I.name as IndexName, CASE WHEN I.is_unique = 1 THEN 'Yes' ELSE 'No' END as 'Unique', I.type_desc COLLATE DATABASE_DEFAULT as Index_Type, '[' + SCHEMA_NAME(T.schema_id) + ']' as 'Schema', '[' + T.name + ']' as TableName, STUFF((SELECT ', [' + C.name + CASE WHEN IC.is_descending_key = 0 THEN '] ASC' ELSE '] DESC' END FROM sys.index_columns IC INNER JOIN sys.columns C ON IC.object_id = C.object_id AND IC.column_id = C.column_id WHERE IC.is_included_column = 0 AND IC.object_id = I.object_id AND IC.index_id = I.Index_id FOR XML PATH('')), 1, 2, '') as Key_Columns, Included_Columns, I.filter_definition, CASE WHEN I.is_padded = 1 THEN 'ON' ELSE 'OFF' END as PAD_INDEX, CASE WHEN ST.no_recompute = 0 THEN 'OFF' ELSE 'ON' END as [Statistics_Norecompute], CONVERT(VARCHAR(5), CASE WHEN I.fill_factor = 0 THEN 100 ELSE I.fill_factor END) as [Fillfactor], CASE WHEN I.ignore_dup_key = 1 THEN 'ON' ELSE 'OFF' END as [Ignore_Dup_Key], CASE WHEN I.allow_row_locks = 1 THEN 'ON' ELSE 'OFF' END as [Allow_Row_Locks], CASE WHEN I.allow_page_locks = 1 THEN 'ON' ELSE 'OFF' END [Allow_Page_Locks] FROM sys.indexes I INNER JOIN sys.tables T ON T.object_id = I.object_id INNER JOIN sys.stats ST ON ST.object_id = I.object_id AND ST.stats_id = I.index_id INNER JOIN sys.data_spaces DS ON I.data_space_id = DS.data_space_id INNER JOIN sys.filegroups FG ON I.data_space_id = FG.data_space_id LEFT OUTER JOIN (SELECT * FROM (SELECT IC2.object_id, IC2.index_id, STUFF((SELECT ', ' + C.name FROM sys.index_columns IC1 INNER JOIN sys.columns C ON C.object_id = IC1.object_id AND C.column_id = IC1.column_id AND IC1.is_included_column = 1 WHERE IC1.object_id = IC2.object_id AND IC1.index_id = IC2.index_id GROUP BY IC1.object_id, C.name, index_id FOR XML PATH('') ), 1, 2, '') as Included_Columns FROM sys.index_columns IC2 GROUP BY IC2.object_id, IC2.index_id) tmp1 WHERE Included_Columns IS NOT NULL ) tmp2 ON tmp2.object_id = I.object_id AND tmp2.index_id = I.index_id WHERE I.is_primary_key = 0 AND I.is_unique_constraint = 0; 

    En bonus, la requête ci-dessous est formatée pour écrire l'index de création et supprimer les scripts d'index:

     SELECT I.name as IndexName, -- Uncommnent line below to include checking for index exists as part of the script --'IF NOT EXISTS (SELECT name FROM sysindexes WHERE name = '''+ I.name +''') ' + 'CREATE ' + CASE WHEN I.is_unique = 1 THEN ' UNIQUE ' ELSE '' END + I.type_desc COLLATE DATABASE_DEFAULT + ' INDEX [' + I.name + '] ON [' + SCHEMA_NAME(T.schema_id) + '].[' + T.name + '] (' + STUFF( (SELECT ', [' + C.name + CASE WHEN IC.is_descending_key = 0 THEN '] ASC' ELSE '] DESC' END FROM sys.index_columns IC INNER JOIN sys.columns C ON IC.object_id = C.object_id AND IC.column_id = C.column_id WHERE IC.is_included_column = 0 AND IC.object_id = I.object_id AND IC.index_id = I.Index_id FOR XML PATH('')), 1, 2, '') + ') ' + ISNULL(' INCLUDE (' + IncludedColumns + ') ', '') + ISNULL(' WHERE ' + I.filter_definition, '') + 'WITH (PAD_INDEX = ' + CASE WHEN I.is_padded = 1 THEN 'ON' ELSE 'OFF' END + ', STATISTICS_NORECOMPUTE = ' + CASE WHEN ST.no_recompute = 0 THEN 'OFF' ELSE 'ON' END + ', SORT_IN_TEMPDB = OFF' + ', FILLFACTOR = ' + CONVERT(VARCHAR(5), CASE WHEN I.fill_factor = 0 THEN 100 ELSE I.fill_factor END) + ', IGNORE_DUP_KEY = ' + CASE WHEN I.ignore_dup_key = 1 THEN 'ON' ELSE 'OFF' END + ', ONLINE = OFF' + ', ALLOW_ROW_LOCKS = ' + CASE WHEN I.allow_row_locks = 1 THEN 'ON' ELSE 'OFF' END + ', ALLOW_PAGE_LOCKS = ' + CASE WHEN I.allow_page_locks = 1 THEN 'ON' ELSE 'OFF' END + ') ON [' + DS.name + '];' + CHAR(13) + CHAR(10) + 'GO' as [CreateIndex], 'DROP INDEX ['+ I.name +'] ON ['+ SCHEMA_NAME(T.schema_id) +'].['+ T.name +'];' + CHAR(13) + CHAR(10) + 'GO' AS [DropIndex] FROM sys.indexes I INNER JOIN sys.tables T ON T.object_id = I.object_id INNER JOIN sys.stats ST ON ST.object_id = I.object_id AND ST.stats_id = I.index_id INNER JOIN sys.data_spaces DS ON I.data_space_id = DS.data_space_id INNER JOIN sys.filegroups FG ON I.data_space_id = FG.data_space_id LEFT OUTER JOIN (SELECT * FROM (SELECT IC2.object_id, IC2.index_id, STUFF((SELECT ', ' + C.name FROM sys.index_columns IC1 INNER JOIN sys.columns C ON C.object_id = IC1.object_id AND C.column_id = IC1.column_id AND IC1.is_included_column = 1 WHERE IC1.object_id = IC2.object_id AND IC1.index_id = IC2.index_id GROUP BY IC1.object_id, C.name, index_id FOR XML PATH('') ), 1, 2, '') as IncludedColumns FROM sys.index_columns IC2 GROUP BY IC2.object_id, IC2.index_id) tmp1 WHERE IncludedColumns IS NOT NULL ) tmp2 ON tmp2.object_id = I.object_id AND tmp2.index_id = I.index_id WHERE I.is_primary_key = 0 AND I.is_unique_constraint = 0 

    Using SQL Server 2016, this gives a complete list of all indexes, with an included dump of each table so you can see how the tables relate. It also shows columns included in covering indexes:

     select t.name TableName, i.name IdxName, c.name ColName , ic.index_column_id ColPosition , i.type_desc Type , case when i.is_primary_key = 1 then 'Yes' else '' end [Primary?] , case when i.is_unique = 1 then 'Yes' else '' end [Unique?] , case when ic.is_included_column = 0 then '' else 'Yes - Included' end [CoveredColumn?] , 'indexes >>>>' [*indexes*], i.*, 'index_columns >>>>' [*index_columns*] , ic.*, 'tables >>>>' [*tables*] , t.*, 'columns >>>>' [*columns*], c.* from sys.index_columns ic join sys.tables t on t.object_id = ic.object_id join sys.columns c on c.object_id = t.object_id and c.column_id = ic.column_id join sys.indexes i on i.object_id = t.object_id and i.index_id = ic.index_id order by TableName, IdxName, ColPosition 

    Based on the accepted answer and two other questions 1 , 2 I have assembled the following query:

     SELECT sys.indexes.name AS IndexName, sys.tables.name AS TableName, REPLACE(( SELECT sys.columns.name + CASE WHEN is_descending_key = 1 THEN ' DESC' ELSE '' END AS [data()] FROM sys.index_columns INNER JOIN sys.columns ON sys.index_columns.object_id = sys.columns.object_id AND sys.index_columns.column_id = sys.columns.column_id WHERE sys.index_columns.object_id = sys.indexes.object_id AND sys.index_columns.index_id = sys.indexes.index_id AND sys.index_columns.is_included_column = 0 ORDER BY sys.index_columns.key_ordinal FOR XML PATH('') ), ' ', ', ') AS KeyColumns, REPLACE(( SELECT sys.columns.name AS [data()] FROM sys.index_columns INNER JOIN sys.columns ON sys.index_columns.object_id = sys.columns.object_id AND sys.index_columns.column_id = sys.columns.column_id WHERE sys.index_columns.object_id = sys.indexes.object_id AND sys.index_columns.index_id = sys.indexes.index_id AND sys.index_columns.is_included_column = 1 ORDER BY sys.index_columns.index_column_id FOR XML PATH('') ), ' ', ', ') AS IncludedColumns, sys.dm_db_index_usage_stats.user_updates, sys.dm_db_index_usage_stats.user_seeks, sys.dm_db_index_usage_stats.user_scans, sys.dm_db_index_usage_stats.user_lookups, sys.dm_db_index_usage_stats.user_seeks + sys.dm_db_index_usage_stats.user_scans + sys.dm_db_index_usage_stats.user_lookups AS total_usage FROM sys.indexes LEFT JOIN sys.tables ON sys.indexes.object_id = sys.tables.object_id LEFT JOIN sys.dm_db_index_usage_stats ON sys.indexes.object_id = sys.dm_db_index_usage_stats.object_id AND sys.indexes.index_id = sys.dm_db_index_usage_stats.index_id WHERE sys.indexes.type <> 0 AND sys.tables.is_ms_shipped = 0 

    This query returns results such as below which shows the list of indexes, their columns and usage. Very helpful in determining which index is performing better than others:

    index list, columns and usage

     sELECT TableName = t.name, IndexName = ind.name, --IndexId = ind.index_id, ColumnId = ic.index_column_id, ColumnName = col.name, key_ordinal, ind.type_desc --ind.*, --ic.*, --col.* FROM sys.indexes ind INNER JOIN sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id INNER JOIN sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id INNER JOIN sys.tables t ON ind.object_id = t.object_id WHERE ind.is_primary_key = 0 AND ind.is_unique = 0 AND ind.is_unique_constraint = 0 AND t.is_ms_shipped = 0 and t.name='CompanyReconciliation' --table name and key_ordinal>0 ORDER BY t.name, ind.name, ind.index_id, ic.index_column_id