Trier le tableau SQL pour afficher la première ligne et la sum de tous les autres

Comment puis-je avoir le tableau suivant pour afficher uniquement la ligne qui a la date la plus proche et la sum de 'Qty' avec le même ID d'article dans une nouvelle colonne.

Comme indiqué ci-dessous,

Name ItemID Date Qty A A0001 25-Feb-14 23 B A0001 01-Apr-14 4 C A0001 18-Jul-14 54 D K0006 03-Mar-14 86 E K0006 11-Jan-14 29 F X0003 27-Sep-14 19 G X0003 12-Nov-14 28 

Voilà à quoi devrait ressembler le résultat,

 Name ItemID Date Qty Total Outstanding A A0001 25-Feb-14 23 81 E K0006 11-Jan-14 29 115 F X0003 27-Sep-14 19 47 

 DECLARE @T TABLE (NAME VARCHAR(10),Itemid VARCHAR(10),da date,qty int) insert into @T(NAME,Itemid,da,qty) values ('A','A0001','2014-02-25',23), ('B','A0001','2014-04-01',4), ('C','A0001','2014-07-18',54), ('D','K0006','2014-03-03',86), ('E','K0006','2014-01-11',29), ('F','X0003','2014-09-27',19), ('G','X0003','2014-11-11',28) ;with cte as ( select *,SUM(qty)OVER(PARTITION BY Itemid )total, ROW_NUMBER()OVER(PARTITION BY Itemid ORDER BY da )RN from @T group by NAME,Itemid,da,qty ) select NAME,Itemid,convert(varchar,da,100)As [date],qty,total from cte WHERE RN = 1 
 SELECT a.Name,a.ItemID,b.Date,a.Qty,b.Total FROM TableA a INNER JOIN (SELECT ItemID,MIN(Date) AS Date,SUM(Qty) AS Tatal FROM TableA GROUP BY ItemID)b ON b.ItemID=a.ItemID AND a.Date=b.Date 
 Select Name, AliasID, DateAlias, Quantity, TotalOutstanding from TableA A join (Select ItemId as AliasID,Min(Date) as DateAlias, Sum(Quantity) as TotalOutstanding from TableA group by ItemID )V on A.ItemID=V.ItemID 

essaye ça:

 with CTE as( select -- M.Name, SUM(M.Qty) TotalOTD,M.ItemID,MIN(M.Date) as MDate from myTestTable M GROUP BY M.ItemID ) select Name, D.ItemID, Date , Qty, TotalOTD from CTE JOIN myTestTable D ON CTE.ItemID=D.ItemID and CTE.MDate=D.date 

SORTIE

 Name ItemID Date Qty TotalOTD A A0001 2014-02-25 23 81 E K0006 2014-01-11 29 115 F X0003 2014-09-27 19 47